location:  Publications → journals
Search results

Search: MSC category 20C99 ( None of the above, but in this section )

 Expand all        Collapse all Results 1 - 4 of 4

1. CMB 2014 (vol 57 pp. 231)

Bagherian, J.
 On the Multiplicities of Characters in Table Algebras In this paper we show that every module of a table algebra can be considered as a faithful module of some quotient table algebra. Also we prove that every faithful module of a table algebra determines a closed subset which is a cyclic group. As a main result we give some information about multiplicities of characters in table algebras. Keywords:table algebra, faithful module, multiplicity of characterCategories:20C99, 16G30

2. CMB 2013 (vol 57 pp. 9)

Alperin, Roger C.; Peterson, Brian L.
 Integral Sets and the Center of a Finite Group We give a description of the atoms in the Boolean algebra generated by the integral subsets of a finite group. Keywords:integral set, characters, Boolean algebraCategory:20C99

3. CMB 2005 (vol 48 pp. 211)

Germain, Jam
 The Distribution of Totatives The integers coprime to $n$ are called the {\it totatives} \rm of $n$. D. H. Lehmer and Paul Erd\H{o}s were interested in understanding when the number of totatives between $in/k$ and $(i+1)n/k$ are $1/k$th of the total number of totatives up to $n$. They provided criteria in various cases. Here we give an if and only if'' criterion which allows us to recover most of the previous results in this literature and to go beyond, as well to reformulate the problem in terms of combinatorial group theory. Our criterion is that the above holds if and only if for every odd character $\chi \pmod \kappa$ (where $\kappa:=k/\gcd(k,n/\prod_{p|n} p)$) there exists a prime $p=p_\chi$ dividing $n$ for which $\chi(p)=1$. Categories:11A05, 11A07, 11A25, 20C99

4. CMB 1997 (vol 40 pp. 352)

Liriano, Sal
 A New Proof of a Theorem of Magnus Using naive algebraic geometric methods a new proof of the following celebrated theorem of Magnus is given: Let $G$ be a group with a presentation having $n$ generators and $m$ relations. If $G$ also has a presentation on $n-m$ generators, then $G$ is free of rank $n-m$. Categories:20E05, 20C99, 14Q99
 top of page | contact us | privacy | site map |