http://dx.doi.org/10.4153/CMB-2011-202-9
7 pages
Published:2012-03-05
Qingying Bu, Department of Mathematics, University of Mississippi, University, MS 38677, USA
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Abstract
For Banach spaces $X$ and $Y$, we show that if $X^\ast$ and $Y$ are
weakly sequentially complete and every weakly compact operator from
$X$ to $Y$ is compact then the space of all compact operators from $X$
to $Y$ is weakly sequentially complete. The converse is also true if,
in addition, either $X^\ast$ or $Y$ has the bounded compact
approximation property.
© Canadian Mathematical Society, 2013
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