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A New Proof of a Theorem of Magnus

  Published:1997-09-01
 Printed: Sep 1997
  • Sal Liriano
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Abstract

Using naive algebraic geometric methods a new proof of the following celebrated theorem of Magnus is given: Let $G$ be a group with a presentation having $n$ generators and $m$ relations. If $G$ also has a presentation on $n-m$ generators, then $G$ is free of rank $n-m$.
MSC Classifications: 20E05, 20C99, 14Q99 show english descriptions Free nonabelian groups
None of the above, but in this section
None of the above, but in this section
20E05 - Free nonabelian groups
20C99 - None of the above, but in this section
14Q99 - None of the above, but in this section
 

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